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2022-10-05A random sample of 85 group leaders, supervisors, and similar personnel revealed that on average a person spent 6.5 years on the job before being promoted. The standard deviation of the sample was 1.7 years.

Using the 0.95 degree of confidence, what is the confidence interval within which the population mean lies?

4.15 and 7.15

6.99 and 7.99

6.49 and 7.49

6.14 and 6.86

The interval estimate can be found from:

Here, we have n = 85, X̄ = 6.5, z = 1.96 (for 95%), and s = 1.7.

Therefore, 6.5 ± 1.96 × 1.7/9.22 and we get 6.14 and 6.86.

2022-10-04

The correlation coefficient between two assets is 1, the standard deviation on asset 1 is 10, and the standard deviation on asset 2 is 20.

What is the standard deviation on a portfolio in which both asset 1 and asset 2 each account for 50% of portfolio value?

206

15

13.2

175

14.4

The covariance is equal to the correlation coefficient multiplied by the two standard deviations. In this case, the covariance equals:

1 × 10 × 20 = 200

The standard deviation of a portfolio with two assets is equal to the square root of the following:

weight of asset 1 (w

In this example, the standard deviation of the portfolio is equal to:

[0.5

The square root of 225 is 15.

2022-10-03

A population consists of all the weights of all defensive tackles on Sociable University's football team:

- Johnson, 204 pounds
- Patrick, 215 pounds
- Junior, 207 pounds
- Kendron, 212 pounds
- Nicko, 214 pounds
- Cochran, 208 pounds

100

40

4

16

Population variance = Sum of squared deviation from the mean / N

The mean is 210.

Population variance = (36 + 25 + 9 + 4 + 16 + 4)/6

= 94/6

= 15.67

Population standard deviation is the square root of the population variance = 3.958.

x | x − Mean | (x − Mean)^{2} |

204 | -6 | 36 |

215 | 5 | 25 |

207 | -3 | 9 |

212 | 2 | 4 |

214 | 4 | 16 |

208 | -2 | 4 |

2022-10-02

Neal Jung, a quantitative analyst with HarvestTime Brokerage, is examining a data sample and has amassed the following information:

- Standard deviation of the sample: 70
- Number of observations: 600
- Sample mean: 812

Given this information, what is the standard error of the estimate? Further, what is the test statistic?

8.370; 4.148

0.014; 11.834

2.858; 11.60

none of these answers

8.370; 1.434

0.014; 857.143

The standard error and test statistic for this example is 2.858 and 4.199, respectively. Therefore, none of these answers is correct.

If the population standard deviation is unknown, as in this example, the standard error of the estimate is found by using the following equation:

where s = the sample standard deviation and n = the number of observations in the sample.

In this example, all of the necessary information has been provided, and the determination of the standard error of the estimate is found as:

Standard error = 70/24.495 = 2.858

Now that the standard error of the estimate has been calculated, the test statistic can be found by using the following equation:

Test statistic = (Sample statistic − Value of the population parameter under the null hypothesis) / Standard error of the sample statistic

Again, all of the necessary information has been provided, and the calculation of the test statistic is found as follows:

Test statistic = (812 − 800) / 2.858 = 4.199

2022-10-01

You are given assets X, Y, and Z, which have expected returns of 5%, 10%, and 15% respectively, and standard deviations of return of 5%, 10%, and 15% respectively. Your client views any return below a level of 0% as unacceptable.

Find the asset that minimizes the probability that the portfolio will fall below 0% annual return, and what is the probability?

Z, 14%

none of these answers

X, 15%

Y, 17%

To answer this question we must follow Roy's safety-first criterion. First, we must find the shortfall level, R

Next, find the standard normal cdf evaluated at the SFRatio for each asset. The probability of shortfall will be N(-SFRatio). For X, Y, and Z, these will be N(-1), N(-1), and N(-1). Since N(-1) = 1 − N(1), and so on, we get 0.1587 for all three.

Thus, all assets equally minimize the probability that the return will fall short of 0, with a probability of approximately 16%.